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36k^2-121=0
a = 36; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·36·(-121)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{17424}=132$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-132}{2*36}=\frac{-132}{72} =-1+5/6 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+132}{2*36}=\frac{132}{72} =1+5/6 $
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